alleryIntegral ∫ 1/sqrt(1 - x²) dx =
Aln(x)
Barctan(x)
Carcsin(x) + C
Darccos(x)
Answer & Solution
Correct answer: C. arcsin(x) + C
∫ dx/sqrt(1-x²) = arcsin(x) + C. (Or -arccos(x) + C', differs by constant.) Standard integral.
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Related questions
In a right triangle, for an acute angle θ, sin θ is defined as:A relation $f$ from $A$ to $B$ is a function if every element of $A$ has:The domain of $f(x)= qrt{4-x^2}$ is:If $(x+1,\,y-2)=(3,\,1)$, then $(x,y)$ equals:The domain of $f(x)= qrt{x-1}$ is:The range of the function $f(x)=x^2,\; x\in\mathbb{R}$ is:The domain of the function $f(x)=\dfrac{1}{x-2}$ is:The reciprocal of sin θ is: