For 3 sets A, B, C: n(A ∪ B ∪ C) =
ARandom
BΣn(individual) - Σn(pairs) + n(A ∩ B ∩ C)
Cn(A) + n(B) + n(C)
Dn(A) × n(B) × n(C)
Answer & Solution
Correct answer: B. Σn(individual) - Σn(pairs) + n(A ∩ B ∩ C)
**Inclusion-exclusion for 3 sets:** n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C).
Generalizes to n sets with alternating signs.
Keep practising Unit 1A2: Trigonometric Functions & Inverse Trig
Browse all Unit 1A2: Trigonometric Functions & Inverse Trig questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
In a right triangle, for an acute angle θ, sin θ is defined as:A relation $f$ from $A$ to $B$ is a function if every element of $A$ has:The domain of $f(x)= qrt{4-x^2}$ is:If $(x+1,\,y-2)=(3,\,1)$, then $(x,y)$ equals:The domain of $f(x)= qrt{x-1}$ is:The range of the function $f(x)=x^2,\; x\in\mathbb{R}$ is:The domain of the function $f(x)=\dfrac{1}{x-2}$ is:The reciprocal of sin θ is: