alleryWhat is $\tan 60^{\circ}$?
A$\dfrac{1}{\sqrt{3}}$
B$1$
C$2$
D$\sqrt{3}$
Answer & Solution
Correct answer: D. $\sqrt{3}$
$\tan 60^{\circ} = \dfrac{\sin 60^{\circ}}{\cos 60^{\circ}} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}$.
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