Per NCERT §7.10, the relationship between total energy E and PE of an orbiting satellite is which?
AE = 0 only at infinity
B|E| = 2 |PE|
CE = |PE|
D|E| = |PE| / 2 (E = PE / 2)
Answer & Solution
Correct answer: D. |E| = |PE| / 2 (E = PE / 2)
NCERT §7.10: |E| = |KE| = (1/2)|PE|. E is negative; magnitude is half of PE magnitude.
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