Per NCERT §7.10 eqn 7.42, the TOTAL mechanical energy of an orbiting satellite is which?
AE = G M m / (R + h)
BE = + G M m / [2 (R + h)]
CE = 0 always
DE = − G M m / [2 (R + h)]
Answer & Solution
Correct answer: D. E = − G M m / [2 (R + h)]
NCERT eqn 7.42: E = KE + PE = GMm/[2(R+h)] − GMm/(R+h) = −GMm/[2(R+h)]. Negative ⇒ bound orbit.
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