Per NCERT §7.10 eqn 7.41, the potential energy of an orbiting satellite at distance (R+h) is which?
A+ G M m / (R + h)
B− G M m / (R + h)
C− G M m / [2 (R + h)]
D+ G M m / [2 (R + h)]
Answer & Solution
Correct answer: B. − G M m / (R + h)
NCERT eqn 7.41: PE = -GMm/(R+h) (V(∞) = 0). Negative because gravity is attractive.
Related questions
Tycho Brahe recorded his observations using:Kepler's three laws describe the motion of:The low escape speed of the moon explains why it has no:The moon's escape speed compared with the earth's is smaller by about:The escape speed for the moon works out to about:The law of periods uses which measurement of the ellipse?By the law of periods, the square of the period is proportional to:The law of areas explains why a planet moves slower when it is: