Per NCERT §7.10 eqn 7.40, the kinetic energy of an orbiting satellite of mass m at distance (R+h) is which?
A+ G M m / (R + h)
B− G M m / [2 (R + h)]
C+ G M m / [2 (R + h)]
D− G M m / (R + h)
Answer & Solution
Correct answer: C. + G M m / [2 (R + h)]
NCERT eqn 7.40: KE = (1/2) m v² with v² = GM/(R+h) gives KE = +GMm/[2(R+h)] (positive).
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