Per NCERT §7.9 eqn 7.37, the time period of a satellite at distance (R+h) from Earth's centre is which?
AT = 2π R / v_orbital
BT = (R + h) / g_surface
CT = 2π (R+h)^(3/2) / √(G M)
DT = √(R + h) / g_surface
Answer & Solution
Correct answer: C. T = 2π (R+h)^(3/2) / √(G M)
NCERT eqn 7.37: T = 2π(R+h)^(3/2) / √(GM). Equivalent to T² = 4π²(R+h)³/(GM) (Kepler's 3rd).
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