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As per your syllabus, the gravitational PE of a particle DOUBLED in distance (r → 2r) from a mass M changes from −GMm/r to which?
A−G M m / (2 r)
B−G M m / (4 r)
C+G M m / (2 r)
D−2 G M m / r
Answer & Solution
Correct answer: A. −G M m / (2 r)
Your syllabus: U(r) = −GMm/r ⇒ U(2r) = −GMm/(2r).
PE rises (less negative); object loses KE if moved out.
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