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The F₂ **phenotypic** ratio of a Mendelian dihybrid cross is:
A3 : 1
B1 : 2 : 1
C9 : 3 : 3 : 1
D1 : 1 : 1 : 1
Answer & Solution
Correct answer: C. 9 : 3 : 3 : 1
Dihybrid TtRr × TtRr → 16 combinations. Phenotype ratio = 9 (T_R_) : 3 (T_rr) : 3 (ttR_) : 1 (ttrr) — the classic 9:3:3:1 dihybrid ratio, illustrating the law of independent assortment.
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