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As per your syllabus, the gravitational PE for two particles of masses m₁ and m₂ separated by r is which?
AV = +G m₁ m₂ / r
BV = G m₁ m₂ / r²
CV = −G m₁ m₂ / r
DV = G (m₁ + m₂) / r
Answer & Solution
Correct answer: C. V = −G m₁ m₂ / r
Your syllabus: V = −Gm₁m₂/r. Convention V(∞) = 0.
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