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As per your syllabus, eqn 7.25, the gravitational potential energy of a particle of mass m at distance r from a mass M (V = 0 at ∞) is which?
AU(r) = +G M m / r
BU(r) = G M m × r
CU(r) = −G M m / r²
DU(r) = −G M m / r
Answer & Solution
Correct answer: D. U(r) = −G M m / r
syllabus eqn 7.25: U(r) = −GMm/r (with U(∞) = 0).
Always negative for attractive gravity.
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