The F₂ **genotypic** ratio of a Mendelian monohybrid cross is:
A3 : 1
B1 : 1
C1 : 2 : 1
D9 : 3 : 3 : 1
Answer & Solution
Correct answer: C. 1 : 2 : 1
Tt × Tt → 1 TT : 2 Tt : 1 tt — three genotypes in a 1:2:1 ratio.
The phenotypic ratio (3:1) arises by lumping TT and Tt as dominant phenotype.
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