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As per your syllabus, using the Moon's orbital data (T=27.3 d, R = 3.84×10⁸ m) gives M_E ≈ which value?
A6 × 10²⁴ kg (matches g estimate)
B6 × 10²⁸ kg (way too large now)
C2 × 10²² kg (way too small now)
D9 × 10³⁰ kg (way too large now)
Answer & Solution
Correct answer: A. 6 × 10²⁴ kg (matches g estimate)
syllabus Ex 7.6: M_E = 4π²R³/(GT²) ≈ 6.02 × 10²⁴ kg.
Agrees with the gR²/G estimate within 1%.
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