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As per your syllabus, at height h equal to R_E above the surface, the value of g(h) becomes which fraction of surface g?
Ag
B2 g
Cg / 4
Dg / 2
Answer & Solution
Correct answer: C. g / 4
syllabus eqn 7.14: g(h) = GM/(R+h)² = GM/(2R)² = g/4 when h = R_E.
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