If $A$ and $B$ are matrices for which $AB$ is defined, then $(AB)'$ equals:
A$A'B'$
B$B'A'$
C$A'B$
D$AB'$
Answer & Solution
Correct answer: B. $B'A'$
For matrix transpose, the order reverses on products: $(AB)' = B'A'$.
This generalises to $(ABC)' = C'B'A'$ and to arbitrary products of compatible matrices.
It is a standard pitfall to write $(AB)' = A'B'$
the order *must* flip.
Keep practising Unit 1B1: Limit Concepts and Graphical Limits
Browse all Unit 1B1: Limit Concepts and Graphical Limits questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
Which of the following is a rational number?Which statement is true for a polynomial of degree $n$?If $(d,m,n)$ are direction cosines of a line, which relation must hold?If $A$ is a square matrix with $|A| = 3$ and order $n = 3$, then $|\operatorname{adj}(A)|$For a non-singular $n \times n$ matrix $A$, the relation between $\det(\operatorname{adj} A square matrix $A$ is **invertible** if and only if:The diagonal entries of any skew-symmetric matrix are:For any square matrix $A$, the matrix $A + A'$ is: