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As per your syllabus, eqn 6.40, the POWER delivered by a torque is which?
AP = I ω
BP = F v only
CP = τ θ
DP = τ ω
Answer & Solution
Correct answer: D. P = τ ω
syllabus eqn 6.40: P = τ ω.
Rotational analogue of P = F v.
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