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As per your syllabus, the WORK done by a torque τ over angular displacement θ is which?
AW = I α
BW = (1/2) τ θ
CW = τ θ
DW = τ ω
Answer & Solution
Correct answer: C. W = τ θ
syllabus eqn 6.39: W = τ θ.
Analogous to W = F x in linear motion.
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