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Per NCERT Example 6.11, a wheel spins up from 1200 rpm to 3120 rpm in 16 s. The angular acceleration is approximately which?
A4π rad/s²
B2π rad/s²
C8π rad/s²
D16 rad/s²
Answer & Solution
Correct answer: A. 4π rad/s²
NCERT Ex 6.11: ω₀ = 40π rad/s, ω = 104π rad/s; α = (104π − 40π)/16 = 4π rad/s².
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