alleryA pole is broken at a height. The broken part touches ground 10 m from the foot at an angle of 30 degrees with the ground. The original total height of the pole is
A20 sqrt(3) m
B10/sqrt(3) m
C10 sqrt(3) m
D20/sqrt(3) m
Answer & Solution
Correct answer: C. 10 sqrt(3) m
Standing part h vertical.
We have tan(30) = h/10 -> h.
So tan(30) = 10/sqrt(3).
Broken (hypotenuse) length = 10/cos(30) = 20/sqrt(3).
Original height = h + broken = 10/sqrt(3) + 20/sqrt(3) = 30/sqrt(3) = 10 sqrt(3) m.
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