alleryIf two chords AB and CD of a circle intersect at P inside the circle, with PA = 4, PB = 9, PC = 6, then PD is
A8
B4
C5
D6
Answer & Solution
Correct answer: D. 6
**Intersecting chords:** PA x PB = PC x PD.
**So 4 x 9 = 6 x PD, giving PD = 36/6 = 6.**
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