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Per NCERT §5.9 eqn 5.16, Hooke's law for an ideal spring states the spring force F_s is which?
AF_s = -k x (restoring)
BF_s = -k x² quadratic
CF_s = k x (along motion)
DF_s = -k / x reciprocal
Answer & Solution
Correct answer: A. F_s = -k x (restoring)
NCERT eqn 5.16: F_s = -kx. Minus sign indicates restoring (toward equilibrium). k is spring constant.
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