alleryThe Cartesian equation of a plane with intercepts 2, 3, 6 on the x, y, z axes is:
A$x/2 + y/3 + z/6 = 1$
B$2x + 3y + 6z = 1$
C$x + y + z = 11$
D$x/3 + y/2 + z/6 = 1$
Answer & Solution
Correct answer: A. $x/2 + y/3 + z/6 = 1$
**Intercept form of plane:** x/p + y/q + z/r = 1 where p, q, r are intercepts on x, y, z axes.
**So x/2 + y/3 + z/6 = 1.**
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