Clemmensen reduction converts $>C=O$ to $>CH_2$ using

A$LiAlH_4$

B$NH_2NH_2/KOH/\Delta$

C$H_2/Ni$

D$Zn(Hg)/conc.\,HCl$

Answer & Solution

Correct answer: D. $Zn(Hg)/conc.\,HCl$

Acidic conditions ($Zn$ amalgam + conc. HCl). Reduces ketones/aldehydes all the way to methylene. Use Wolff–Kishner instead if the substrate is base-stable but acid-sensitive.

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**Clemmensen reduction** converts $>C=O$ to $>CH_2$ using

Keep practising Aldehydes, Ketones and Carboxylic Acids

Clemmensen reduction converts $>C=O$ to $>CH_2$ using