alleryA long straight wire carries $5$ A. The magnetic field $0.10$ m away from the wire is:
A$1.0\times 10^{-5}$ T, by $B = \mu_0 I/(2\pi r)$
B$5\times 10^{-7}$ T, ignoring the $2\pi$ factor here
C$1.0$ T, ignoring all scaling on the formula
DZero, since the wire is straight, not coiled
Answer & Solution
Correct answer: A. $1.0\times 10^{-5}$ T, by $B = \mu_0 I/(2\pi r)$
$B = 4\pi\times 10^{-7}\cdot 5/(2\pi\cdot 0.1) = 1.0\times 10^{-5}$ T.
Keep practising Moving Charges and Magnetism
Browse all Moving Charges and Magnetism questions for AP Intermediate 2nd Year, or explore more Physics topics.
Related questions
The magnetic field at a distance $r$ from a LONG STRAIGHT wire carrying current $I$ isThe magnetic force on a charge $q$ moving with velocity $\vec{v}$ in a magnetic field $\veMatch the magnetism termWork done by a magnetic forceA bismuth bar near a strong magnet on the lab table is:Materials are classified by which quantity?Magnetic field lines of a bar magnet form:The tip of a magnet pointing to geographic north is its: