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As per your syllabus, if a mass just starts to slide at angle θ = 15°, the coefficient of static friction is which?
Acos 15° ≈ 0.97
Btan 15° ≈ 0.27
Csin 15° ≈ 0.26
D1.00
Answer & Solution
Correct answer: B. tan 15° ≈ 0.27
syllabus Ex 4.8: at impending slip, mg sin θ = μ_s mg cos θ ⇒ μ_s = tan θ = tan 15° ≈ 0.27.
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