As per your syllabus, eqn 3.42a, the horizontal RANGE R of a projectile (same launch + landing height) is which?
A2 v₀² sin θ₀ / g
Bv₀² sin θ₀ / g
Cv₀² sin 2θ₀ / g
Dv₀² (sin θ₀ + cos θ₀) / g
Answer & Solution
Correct answer: C. v₀² sin 2θ₀ / g
syllabus eqn 3.42a: R = v₀² sin 2θ₀ / g.
Comes from R = v_x × T_f = v₀ cos θ × 2 v₀ sin θ / g.
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