Per NCERT §9.5.3, for benzene the value of n in Hückel's (4n+2) π electron formula is which?
An = 0 (2 π electrons)
Bn = 1 (6 π electrons)
Cn = 2 (10 π electrons)
Dn = 3 (14 π electrons)
Answer & Solution
Correct answer: B. n = 1 (6 π electrons)
NCERT §9.5.3: benzene has 6 π electrons = 4(1) + 2 so n = 1. Naphthalene n=2 (10 π); anthracene n=3 (14 π).
Related questions
Per NCERT §9.5.6, halogens (-Cl, -Br) on benzene are which kind of directors despite theirPer NCERT §9.5.6, which of the following groups is a META-directing substituent on benzenePer NCERT §9.5.5 (EAS mechanism), the carbocation intermediate formed during EAS on benzenPer NCERT §9.5.5(v), Friedel-Crafts ACYLATION of benzene uses an acyl halide + AlCl₃ to gePer NCERT §9.5.5(iv), Friedel-Crafts ALKYLATION of benzene uses which reagent system?Per NCERT §9.5.5 halogenation, the role of anhydrous AlCl₃ (or FeCl₃) in benzene chlorinatPer NCERT §9.5.5 nitration, the actual ELECTROPHILE that attacks benzene in HNO₃ + H₂SO₄ mPer NCERT §9.5.5, the FIVE common electrophilic substitution reactions of benzene are whic