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As per your syllabus, for benzene the value of n in Hückel's (4n+2) π electron formula is which?
An = 0 (2 π electrons)
Bn = 1 (6 π electrons)
Cn = 2 (10 π electrons)
Dn = 3 (14 π electrons)
Answer & Solution
Correct answer: B. n = 1 (6 π electrons)
Your syllabus: benzene has 6 π electrons = 4(1) + 2 so n = 1. Naphthalene n=2 (10 π)
anthracene n=3 (14 π).
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