Per NCERT §9.4.3 (addition of HBr), HBr addition to propyne gives which Markovnikov product?
A3-Bromoprop-1-yne
B1-Bromopropene
C2-Bromopropene
D1,1-Dibromopropane
Answer & Solution
Correct answer: C. 2-Bromopropene
NCERT §9.4.3: per Markovnikov, Br to more substituted C of triple bond → 2-bromopropene (further HBr would give 2,2-dibromo).
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