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As per your syllabus, HBr addition to propyne gives which Markovnikov product?
A3-Bromoprop-1-yne
B1-Bromopropene
C2-Bromopropene
D1,1-Dibromopropane
Answer & Solution
Correct answer: C. 2-Bromopropene
Your syllabus: per Markovnikov, Br to more substituted C of triple bond
→ 2-bromopropene (further HBr would give 2,2-dibromo).
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