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Which half-reaction from the notes represents reduction?
A$Zn \rightarrow Zn^{2+} + 2e^{-}$
B$Cu^{2+} + 2e^{-} \rightarrow Cu$
C$Cu \rightarrow Cu^{2+} + 2e^{-}$
D$Zn^{2+} \rightarrow Zn + 2e^{-}$
Answer & Solution
Correct answer: B. $Cu^{2+} + 2e^{-} \rightarrow Cu$
Reduction involves gain of electrons, so electrons must appear on the reactant side. In $Cu^{2+} + 2e^{-} \rightarrow Cu$, copper ions gain electrons to form copper metal.
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