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What is the change of base formula for log_b(x) using base k?

Alog_k(b) / log_k(x)
Blog_k(x) / log_k(b)
Clog_k(x) * log_k(b)
Dlog_k(x) - log_k(b)
Answer & Solution
Correct answer: B. log_k(x) / log_k(b)
Converting to base k computes log_k of the argument divided by log_k of the original base.
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