alleryFor any polynomial r, gcd(p, q) equals which equivalent GCD expression?
Agcd(p + q, rq)
Bgcd(p, q - r)
Cgcd(q, p + rq)
Dgcd(r, p * q)
Answer & Solution
Correct answer: C. gcd(q, p + rq)
Adding a polynomial multiple of q to p leaves their common divisors and GCD unchanged.
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