alleryHow does the squared difference with a reciprocal (x - 1/x)^2 expand?
Ax^2 + 1/x^2 + 2
Bx^2 - 1/x^2 - 2
Cx^2 + 1/x^2 - 4
Dx^2 + 1/x^2 - 2
Answer & Solution
Correct answer: D. x^2 + 1/x^2 - 2
Squaring the difference produces x^2 - 2(x)(1/x) + 1/x^2 = x^2 + 1/x^2 - 2.
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