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Per NCERT §7.3 rules, the oxidation number of chromium in K₂Cr₂O₇ is which?
A+6
B+3
C+7
D+4
Answer & Solution
Correct answer: A. +6
NCERT §7.3: 2(+1) + 2Cr + 7(−2) = 0 ⇒ 2Cr = +12 ⇒ Cr = +6.
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