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As per your syllabus, the oxidation number of oxygen in a SUPEROXIDE (e.g. KO₂, RbO₂) is which?
A+1 (only with fluorine)
B−2 (normal oxide)
C−1/2
D−1 (peroxide bond)
Answer & Solution
Correct answer: C. −1/2
syllabus rule 3: KO₂ K = +1, so each O = −1/2.
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