For the reaction $2NO(g) + 2H_2(g) \to N_2(g) + 2H_2O(g)$, rate = $k[NO]^2[H_2]$. The orders w.r.t. NO, $H_2$, and the overall order are:
A1, 1, 2
B1, 2, 3
C2, 1, 3
D2, 2, 4
Answer & Solution
Correct answer: C. 2, 1, 3
Exponent of [NO] = 2, of [H₂] = 1. Overall order = 2 + 1 = 3. So second order in NO, first in H₂, third overall.
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