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Per NCERT §6.14, for a salt M₂X(s) ⇌ 2 M⁺(aq) + X²⁻(aq) of molar solubility S, the SOLUBILITY PRODUCT Ksp equals which?
A4S³
BS³
C2S²
DS²
Answer & Solution
Correct answer: A. 4S³
NCERT §6.14: [M⁺]=2S, [X²⁻]=S, so Ksp = (2S)²·S = 4S³.
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