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HomeNEET UGchemistryc11buffer_ksp_solubility › Per NCERT §6.14, for a sparingly soluble salt MX…

Per NCERT §6.14, for a sparingly soluble salt MX(s) ⇌ M⁺(aq) + X⁻(aq) with molar solubility S, the SOLUBILITY PRODUCT Ksp equals which?

AS
B
C
D2S
Answer & Solution
Correct answer: B. S²
NCERT §6.14: Ksp = [M⁺][X⁻] = S × S = S².
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