Home › CBSE Class 11 › Chemistry › Chemical Equilibrium › Per NCERT §6.13 (Henderson-Hasselbalch, eqn 6.40…
Per NCERT §6.13 (Henderson-Hasselbalch, eqn 6.40-6.41), the pH of an acidic buffer is given by which expression?
ApH = pKa + log([salt]/[acid])
BpH = pKa × log([salt]/[acid])
CpH = pKw − pKa
DpH = pKa − log([salt]/[acid])
Answer & Solution
Correct answer: A. pH = pKa + log([salt]/[acid])
NCERT eqn 6.40: Henderson-Hasselbalch — pH = pKa + log([A⁻]/[HA]).
Related questions
For Fe³⁺(aq) + SCN⁻(aq) ⇌ [Fe(SCN)]²⁺(aq), adding more KSCN causes the Fe³⁺ concentration The solubility of carbon dioxide in a soft drink falls as temperature rises because dissolWhen the temperature of an exothermic reaction at equilibrium is raised, the equilibrium cAdding a catalyst to a reversible reaction at equilibrium:A sealed flask of reacting gases shows no colour change for an hour. What is actually happBesides VSEPR and the Kossel Lewis approach, which two theories are listed?Which theory is abbreviated VSEPR?Why can lattice enthalpy not be calculated directly from attraction and repulsion alone?