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As per your syllabus, eqn 6.28, the ionic product of water Kw = [H⁺][OH⁻] at 298 K has which value?
A1.0 × 10⁻¹⁴
B1.0 × 10¹⁴
C1.0 × 10⁻⁷
D1.0 × 10⁻¹⁰
Answer & Solution
Correct answer: A. 1.0 × 10⁻¹⁴
syllabus eqn 6.28: at 298 K, [H⁺] = [OH⁻] = 1.0 × 10⁻⁷ M ⇒ Kw = 1.0 × 10⁻¹⁴.
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