For the reaction A + B → P, doubling [A] (at constant [B]) doubles the rate; doubling [B] (at constant [A]) quadruples the rate. The rate law is:
Arate = $k[A][B]$
Brate = $k[A]^2[B]^2$
Crate = $k[A][B]^2$
Drate = $k[A]^2[B]$
Answer & Solution
Correct answer: C. rate = $k[A][B]^2$
Doubling [A] doubles rate ⇒ order in A = 1. Doubling [B] makes rate × 4 = 2² ⇒ order in B = 2. So rate = $k[A][B]^2$, overall third order.
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