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As per your syllabus, eqn 6.15, the relationship between Kp and Kc for a gaseous reaction is which?
AKp = Kc / (RT)^Δn
BKp = Kc (RT)^Δn
CKp = Kc × Δn
DKp = Kc + RT
Answer & Solution
Correct answer: B. Kp = Kc (RT)^Δn
syllabus eqn 6.15: Kp = Kc (RT)^Δn, where Δn = moles gaseous products − moles gaseous reactants.
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