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As per your syllabus, eqn 6.8, if Kc is the equilibrium constant of a forward reaction, the equilibrium constant of the REVERSE reaction equals which?
AKc
BKc²
C1 / Kc
D−Kc
Answer & Solution
Correct answer: C. 1 / Kc
syllabus eqn 6.8: K_reverse = 1/K_forward at the same temperature.
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