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Per NCERT Problem 5.6, 1 g graphite burnt in a bomb calorimeter (heat capacity 20.7 kJ/K) raises temperature by 1 K. What is ΔH (= ΔU here) for combustion per MOLE of graphite?
A−393.5 kJ/mol
B+20.7 kJ/mol
C−20.7 kJ/mol
D−2.48 × 10² kJ/mol
Answer & Solution
Correct answer: D. −2.48 × 10² kJ/mol
Per NCERT Problem 5.6, q = −C_V ΔT = −20.7 kJ for 1 g. Per mole: ×12/1 = −248.4 ≈ −2.48×10² kJ/mol. Δn_g=0 ⇒ ΔH = ΔU.
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