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Per NCERT §5.5(b), the ENTHALPY OF ATOMIZATION Δ_a H° of dihydrogen is which value, and how does it relate to bond dissociation enthalpy?
A+435 kJ/mol — equal to the H-H bond dissociation enthalpy (since H₂ is diatomic)
B+108 kJ/mol
C+1665 kJ/mol
D−74.81 kJ/mol
Answer & Solution
Correct answer: A. +435 kJ/mol — equal to the H-H bond dissociation enthalpy (since H₂ is diatomic)
Per NCERT §5.5(b), H₂ → 2H, Δ_a H° = 435 kJ/mol = bond dissociation enthalpy of H-H. For diatomic molecules they're identical.
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