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Which proposed counts cannot belong to a convex polyhedron?

A7 faces, 8 vertices, 14 edges
B8 faces, 12 vertices, 18 edges
C5 faces, 6 vertices, 9 edges
D6 faces, 8 vertices, 12 edges
Answer & Solution
Correct answer: A. 7 faces, 8 vertices, 14 edges
Only 7 + 8 − 14 equals one rather than two, so that proposal violates Euler's relation.
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