alleryStart learning →Eigenvalues λ of a square matrix A satisfy
Adet(A − λI) = 0
Btr(A − λI) = 0
CAλ = 0
DAv = λA for any vector v
Answer & Solution
Correct answer: A. det(A − λI) = 0
Eigenvalues are roots of the characteristic polynomial det(A − λI) = 0. The corresponding non-zero v in (A − λI)v = 0 is the eigenvector.
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