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HomeCLATlawclat_ug_topup_r2 › A man walks 4 km north, then 3 km east. His stra…

A man walks 4 km north, then 3 km east. His straight-line distance from the starting point is

A5 km
B6 km
C7 km
D8 km
Answer & Solution
Correct answer: A. 5 km
Apply Pythagoras: √(4² + 3²) = √(16 + 9) = √25 = 5 km. The classic 3-4-5 right triangle.
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