Start learning →

A man walks 4 km north, then 3 km east. His straight-line distance from the starting point is

A5 km
B6 km
C7 km
D8 km
Answer & Solution
Correct answer: A. 5 km
**Apply Pythagoras:** √(4² + 3²) = √(16 + 9) = √25 = 5 km. The classic 3-4-5 right triangle.
Practise this question with Quill — CLAT →

Keep practising Clat Ug Topup

Browse all Clat Ug Topup questions for CLAT, or explore more Law topics.

Start a Clat Ug Topup lesson →